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Draw a circle of center O and radius 3cm. Draw tangents PA and PB from external point P to the circle,such that PA=PB=2√10 |
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Answer» Drawn , a REQUIRED circle •Given, radius = 3 cm PA = PB = 2√10 cm •In triangle OAP •By Pythagoras theorem OA² + PA² = OP² 3² + (2√10)² = OP² 9+40 = OP² OP² = 49 OP = 7 cm • Now draw a point P 7cm away from the circle and join OP • Now from point P MAKE two lines make two TANGENTS. • Tangents will measure 2√10cm |
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