Related InterviewSolutions

• Two waves of wavelength 50 cm and 51 cm produce 12 beat/s . The speed of sound isA. `340 ms^(-1)`B. `332 ms^(-1)`C. `153 ms^(-1)`D. `306 ms^(-1)`
• After reflection from the open end a transverse progressive wave `y_1 =A sin 2pi (t//T-x//lambda ) ` travels along the direction of negative X-axis The equation of the reflected wave will beA. `y^(2) =A sin 2pi (t//T-lambda //x)`B. ` y^(2) =-A sin 2pi (t//T+x//lambda ) `C. `y_2 =A sin 2pi (t//T) +x //lambda ) `D. ` y_2=A cos 2pi (t//T- x//lambda ) `
• A wave is described by the equation `y = (1.0 mm) sin pi((x)/(2.0 cm) - (t)/(0.01 s))`. (a) Find time period and wavelength. (b) Find the speed of particle at `x = 1.0 cm` and time `t = 0.01 s`. ( c ) What are the speed of the partcle at `x = 3.0 cm`, `5.0 cm and 7.0 cm` at `t = 0.01 s`? (d) What are the speeds of the partcle at `x =1.0 cm` at `t = 0.011` , `0.012 and 0.013 s`?
• A transverse wave along a string is given by `y = 2 sin (2pi (3t - x) + (pi)/(4))` where x and y are in cm and t in second. Find acceleration of a particle located at x = 4 cm at t = 1s.A. `36 sqrt(2)pi^(2) cm//s^(2)`B. `36 pi^(2) cm//s^(2)`C. `-36 sqrt(2)pi^(2)cm//s^(2)`D. `-36 pi^(2) cm//s^(2)`
• Assertion :on reflection from a rigid boundary (denser medium) there is a complete reversal of phase. Reason : This is because o reflection at a denser medium. Both the particle velocity and wave velocity are reversed in sign.A. Assertion is True ,Reason is True , Reason is a correct explanation for AssertionB. Assertion is True, Reason is True , Reason is not a correct explanation for AssertionC. Assertion is True ,Reason is FalseD. Assertion is False but , Reason is True
• The displacement `y` of a wave travelling in the x-direction is given by `y = 10^(-4) sin ((600t - 2x + (pi)/(3))meters` where `x` is expressed in meters and `t` in seconds. The speed of the wave-motion, in `ms^(-1)`, isA. 200B. 300C. 600D. 1200
• Two engines pass each other in opposite directions with a velocity of `60 kmh^(-1)`each . One of them is emitting a note of frequency 540.Calculate the frequencies heard in the other engine before and after they have passed each other.Given velocity of sound `=316.67 ms^(-1)`.
• A source is approaching towoed a wall as shown in figure .We have three observes `O_(1),O_(2) `and `O_(3). observer `O_(2) is over the source itself . Let `f_(1),f_(2)and `f_(3) be the beat frequencires heard by `O_(1),O_(2) `and `O_(3)` between direct sound from the source and reflected sound from the wall . then A. (a)`f_(3)=0B. `f_(1)gt f_(2)`C. both(a) and (b) are wrongD. both (a) and (b) are correct
• Two sound waves trevelling in same direction can be represented as `y_(1)=(0.02 mm)sin [(400 pi rad s^(-1))(x/(330 ms^(-1))-t)]` And `y_(2)=(0.02 mm)sin [(404 pi rad s^(-1))(x/(330 ms^(-1))-t)]` The waves superimpose. (i) Find distance between two nearest points where an intensity maximum is recorded simultaneously. (ii) Find the time gap between two successive intensity maxima at a given point.
• Two trains A and B are moving on parallel tracks in opposite direction at same speed of `30 ms^( –1)`. Just when the engines of the two trains are about to cross, the engine of train A begins to sound a horn. The sound of the horn is composed of components varying in frequency from `900 Hz` to 1200 Hz. The speed of sound in air is `330 ms^( –1)`. (a) Find the frequency spread (range of frequencies) for the sound heard by a passenger in train A. (b) Find the frequency spread heard by a passenger in train B.