Does 5047/3500 have a terminating or non terminating decimal. If yes a

1.	Does 5047/3500 have a terminating or non terminating decimal. If yes after how many places will it terminate?
Answer» ong>ANSWER: Yes, It has a terminating decimal because A rational number will have terminating decimal expansion, if the factors of the denominator is in the form of $2^{n}5^{m}$ . The decimal expansion of 5047/3500 will terminate after 3 places.* Step-by-step explanation: 5047/3500, this can be divided by 7 as there is 7 as a factor in both numbers. 721/500, now the denominator contains the factors, 4 and 125, which can be written in the form $2^{2}5^{3}$ . Now we should make the powers of $2^{2}5^{3}$ equal. To make that we NEED to multiply 2 to $2^{2}5^{3}$ and to the NUMERATOR also. Then it will become $2^{3}5^{3}$ and the numerator will become 7212= 1442 Now, 1442 / $(25)^{3}$ =1442/ $10^{3}$ , now the decimal expansion will terminate after 3 places, because the 10 is raised to the POWER of 3.

Does 5047/3500 have a terminating or non terminating decimal. If yes after how many places will it terminate?

Answer»

Yes, It has a terminating decimal because A rational number will have terminating decimal expansion, if the factors of the denominator is in the form of $2^{n}*5^{m}$ . The decimal expansion of 5047/3500 will terminate after 3 places.

Step-by-step explanation:

5047/3500, this can be divided by 7 as there is 7 as a factor in both numbers.

721/500, now the denominator contains the factors, 4 and 125, which can be written in the form $2^{2}*5^{3}$ .

Now we should make the powers of $2^{2}*5^{3}$ equal.

To make that we NEED to multiply 2 to $2^{2}*5^{3}$ and to the NUMERATOR also.

Then it will become $2^{3}*5^{3}$ and the numerator will become 721*2= 1442

Now, 1442 / $(2*5)^{3}$ =1442/ $10^{3}$ , now the decimal expansion will terminate after 3 places, because the 10 is raised to the POWER of 3.

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