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ong>Answer:

Define impulse. Two BLOCKS of masses 10g and 30g are fastened to the ends of a cord which passes over a frictionless pulley. The 10g block rests on the table. What minimum force MUST be applied on the 10g block to keep it on the table? What will be the tension in the cord under this condition? What will be the acceleration of the system and the tension in the cord when the force is withdrawn?

(g=9.8ms

−2

)

EXPLANATION:

ANSWER

consider the weight 30GM is going to downward with the acceleration be a.

And the tension ACTING in upward direction.

Now,

f=m

1

g−T

m

1

a=m

1

g−T

and m

1

=30gm

And the 10gm object will also move with the same acceleration.

Then, T=m

2

a and m

2

=10gm

thus, m

1

a=m

1

g−m

2

a

Therefore,

m

1

+m

2

m

2

g

a=

10+30

30×10

a=

40

300

=

4

30

=7.5

Hence,

a=7.5m/s

2

and the tension T in the string =

1000

10

7.5

T=0.075N

Hence, Force required to stop the object of 10gm mass is 0.075N


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