Do you like my pfp and i also need help with some hw

1.	Do you like my pfp and i also need help with some hw
Answer» *ANSWERS: Let speed of Train B = x 120/x= √(9/16) => x = 4 x 120/3 = 160 km/hr Note : This can be solved WITHOUT using this formula by using fundamentals of TIME, Speed & Distance. Derivation of formula : Let x be the total distance and t be the time at which the two trains meet. Let s1, s2 are speeds of train A, train B RESPECTIVELY and a & b are the times at which they reach the DESTINATION after they meet. x = t(s1 + s2) ...(1) x = (t + a)s1 ...(2) x = (t + b)s2 ...(3) Solving (1), (2) & (3) t = √(ab) => Time to meet is the Geometric Mean of individual time after meeting. => s1/s2 = √(b/a) $\\$

Answer»

ANSWERS:

Let speed of Train B = x

120/x= √(9/16)

=> x = 4 x 120/3 = 160 km/hr

Note : This can be solved WITHOUT using this formula by using fundamentals of TIME, Speed & Distance.

Derivation of formula :

Let x be the total distance and t be the time at which the two trains meet.

Let s1, s2 are speeds of train A, train B RESPECTIVELY and a & b are the times at which they reach the DESTINATION after they meet.

x = t(s1 + s2) ...(1)

x = (t + a)s1 ...(2)

x = (t + b)s2 ...(3)

Solving (1), (2) & (3)

t = √(a*b)

=> Time to meet is the Geometric Mean of individual time after meeting.

=> s1/s2 = √(b/a)

$\\$