Saved Bookmarks
| 1. |
DO THIS GUYS TO BE MARKED BRAINLIEST...................range for which the function f(x) = 2x²– log x, for x > 0 decreases, is |
|
Answer» Solution:- The CONDITION in which the value decreases=f'(x)>0 now f'(x)=4x-1/x ×1/ln(1) f'(x)=4x-1/x since we have to find DECREASING condition so, f'(x)<0 {4x^2-1}/x<0 representing it on the NUMBER line it is given previously that x>0,so we can't cosider left of 0 putting a number,1/4,in the given term we get f'(1/4)=(4×1/16-1)/{1/4)}=-3,which is less than 0 similarly putting any number between 0 and 1/2 ,we will get a number<0 hence range is (0,1/2) {hope it helps}. |
|