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Divide the polynomial (6x³ + 11x² - 10x - 7) by the binomial (2x + 1). Write the quotient and the remainder. |
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Answer» Quotient = 3x² + 4x - 7 Remainder = 0 Step-by-step explanation: Divide the POLYNOMIAL (6x³ + 11x² - 10x - 7) by the binomial (2x + 1). Write the quotient and the remainder. 6x³ + 11x² - 10x - 7 = 6x³ + 3x² + 8x² + 4x - 14X - 7 + 0 = 3x²(2x + 1) + 4x(2x + 1) - 7(2x + 1) + 0 = (3x² + 4x - 7)(2x+1) + 0 ((6x³ + 11x² - 10x - 7)/(2x + 1) = ((3x² + 4x - 7)(2x+1) + 0) / (2x + 1) CANCELLING 2x + 1 from numerator & DENOMINATOR = 3x² + 4x - 7 Quotient = 3x² + 4x - 7 Remainder = 0 |
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