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Divide the polynomial 3x²-4x³-3x-1 by x-1 |
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Answer» ong>Answer: Given that, If we divide f(x) by (x -3), the remainder of this polynomial will be f(3) f(3) = 4(3)^3 - 2(3^2) + 4(3) -7 = 4. 27 - 2. 9 + 12 - 7 = 108 - 18 + 12 - 7 = 95 So, the the remainder is 95. Here, Dividend = 4x^3 - 2x^2 + 4x -7 Divisor = 3 Remainder = 95 We know, Dividend = Divisor × Quotient + Remainder => 4x^3 - 2x^2 + 4x -7 = 3 × Quotient +95 => 4x^3 - 2x^2 + 4x -7 - 95 = 3 Quotient => 3 Quotient = 4x^3 - 2x^2 + 4x -7 - 95 => 3Quotient = 4x^3 - 2x^2 + 4x -102 => Quotient = (4x^3 - 2x^2 + 4x -102)/3 If you don’t apply this formula, it will take much time and will be harder for you. Good luck and thank you for requesting me. |
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