Divide:(i) (3/8) by (5/9)(ii) 3 (1/4) by (2/3)(iii) (7/8) by 4 (1/2)(i

1.	Divide:(i) (3/8) by (5/9)(ii) 3 (1/4) by (2/3)(iii) (7/8) by 4 (1/2)(iv) 6 (1/4) by 2 (3/5)
Answer» (i) Given (3/8) by (5/9) From the rule of division of fraction we know that (a/b) ÷ (c/d) = (a/b) × (d/c) (3/8)/ (5/9) = (3/8) × (9/5) = (3 × 9) / (8 × 5) = (27/40) (ii) Given 3 (1/4) by (2/3) Converting 3 (1/4) to improper we get (13/4) From the rule of division of fraction we know that (a/b) ÷ (c/d) = (a/b) × (d/c) (13/4)/ (2/3) = (13/4) × (3/2) = (13 × 3) / (4 × 2) = (39/8) = 4 (2/7) (iii) Given (7/8) by 4 (1/2) Converting 4 (1/2) to improper we get (9/2) From the rule of division of fraction we know that (a/b) ÷ (c/d) = (a/b) × (d/c) (7/8)/ (9/2) = (7/8) × (2/9) = (7 × 2) / (8 × 9) = (14/72) = (7/36) (iv) Given 6 (1/4) by 2 (3/5) Converting 6 (1/4) and 2 (3/5) to improper we get (25/4) and (13/5) From the rule of division of fraction we know that (a/b) ÷ (c/d) = (a/b) × (d/c) (25/4)/ (13/5) = (25/4) × (5/13) = (25 × 5) / (4 × 13) = (75/52) = 2 (21/52)

Divide:(i) (3/8) by (5/9)(ii) 3 (1/4) by (2/3)(iii) (7/8) by 4 (1/2)(iv) 6 (1/4) by 2 (3/5)

Answer»

(i) Given (3/8) by (5/9)

From the rule of division of fraction we know that (a/b) ÷ (c/d) = (a/b) × (d/c)

(3/8)/ (5/9) = (3/8) × (9/5)

= (3 × 9) / (8 × 5)

= (27/40)

(ii) Given 3 (1/4) by (2/3)

Converting 3 (1/4) to improper we get (13/4)

From the rule of division of fraction we know that (a/b) ÷ (c/d) = (a/b) × (d/c)

(13/4)/ (2/3) = (13/4) × (3/2)

= (13 × 3) / (4 × 2)

= (39/8)

= 4 (2/7)

(iii) Given (7/8) by 4 (1/2)

Converting 4 (1/2) to improper we get (9/2)

From the rule of division of fraction we know that (a/b) ÷ (c/d) = (a/b) × (d/c)

(7/8)/ (9/2) = (7/8) × (2/9)

= (7 × 2) / (8 × 9)

= (14/72)

= (7/36)

(iv) Given 6 (1/4) by 2 (3/5)

Converting 6 (1/4) and 2 (3/5) to improper we get (25/4) and (13/5)

From the rule of division of fraction we know that (a/b) ÷ (c/d) = (a/b) × (d/c)

(25/4)/ (13/5) = (25/4) × (5/13)

= (25 × 5) / (4 × 13)

= (75/52)

= 2 (21/52)