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Divide:acx2 + (bc + ad)x + bd by (ax + b) |
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Answer» We have, (acx2 + (bc + ad) x + bd) / (ax + b) (acx2 + (bc + ad) x + bd) / (ax + b) = cx + d + 0/ (ax + b) = cx + d ∴ The answer is (cx + d). |
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