1.

Divide:acx2 + (bc + ad)x + bd by (ax + b)

Answer»

We have,

(acx2 + (bc + ad) x + bd) / (ax + b)

(acx2 + (bc + ad) x + bd) / (ax + b) 

= cx + d + 0/ (ax + b)

= cx + d

∴ The answer is (cx + d).



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