Divide:(a2 + 2ab + b2) – (a2 + 2ac + c2) by 2a + b + c – InterviewSolution

1.

Divide:(a2 + 2ab + b2) – (a2 + 2ac + c2) by 2a + b + c

Answer»

We have,

[(a² + 2ab + b²) – (a² + 2ac + c²)] / (2a + b + c)

[(a² + 2ab + b²) – (a² + 2ac + c²)] / (2a + b + c)

= b – c + 0/(2a + b + c)

= b – c

∴ The answer is (b – c)

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