DIVIDE 56 INTO TWO PARTS SUCH THAT THREE TIMES THE FIRST PART EXCEEDS

1.	DIVIDE 56 INTO TWO PARTS SUCH THAT THREE TIMES THE FIRST PART EXCEEDS ONE THIRD OF THE SECOND BY 48. THE PARTS ARE.
Answer» let the second PART be x so the FIRST part is x/3+48 now x/3+48+x=56 (x+3x)/3=56-48 x+3x=8×3 4x=24 x=24/4=6 therefore the second part =x=6 and first part =x/3+48=6/3+48=2+48=50 hope it HELPED you pls mark as BRAINLIEST

DIVIDE 56 INTO TWO PARTS SUCH THAT THREE TIMES THE FIRST PART EXCEEDS ONE THIRD OF THE SECOND BY 48. THE PARTS ARE.

Answer»

let the second PART be x

so the FIRST part is x/3+48

now x/3+48+x=56

(x+3x)/3=56-48

x+3x=8×3

4x=24

x=24/4=6

therefore the second part =x=6

and first part =x/3+48=6/3+48=2+48=50

hope it HELPED you

pls mark as BRAINLIEST

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DIVIDE 56 INTO TWO PARTS SUCH THAT THREE TIMES THE FIRST PART EXCEEDS ONE THIRD OF THE SECOND BY 48. THE PARTS ARE.

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