Saved Bookmarks
| 1. |
Divide 56 into 4 parts which are in AP such that the ratio of the products of its extremes to the products of its means is 5:6. |
|
Answer» 4 no =a-3d,a-d,a+d,a+3dsum , 4a=56a=14(a-3d)(a+3d)/(a-d)(a+d)=5:66(a²-9d²)=5(a²-d²)a²=54d² - 5d²14² =49d²d²=14² /7²d=±14/7=±2for d=2, a-3d=14-6=8a-d=14-2=12a+d=14+2=16a+3d=14+6=20Numbers are 8,12,16,20 |
|