1.

Divide 240 into two parts such that one third of one part may be less than the by 72

Answer»

Answer:

Let the first part be a

Second part = 240 - a

According to question,

a/3 + 72 = 240 - a

=> a/3 + a = 240 - 72

=> 4a/3 = 168

=> a = 168 × 3 /4

=> a = 42 × 3

=> a = 126

First part = 126

Second part = 240 - a

= 240 - 126

= 114

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