Divide 216 into 3 parts which are in AP and the product of two smaller

1.	Divide 216 into 3 parts which are in AP and the product of two smaller parts is 5040pls help me!!!
Answer» Step-by-step explanation: Let the THREE NUMBERS are a-d, a ,a+d Sum of these three numbers is 216 (a-d)+a+(a+d)=216 3a =216 =72 a=72 Product of two smaller parts will be 5040 $(a - d)a = 5040$ according to formula (72-d) 72=5040 Divide both sides by 72 (72-d)=70 72-70=d 2-d We have a number A =72 and D=2 so,three numbers are : a-d=72-2=70 a=72 a+d=72+2=74 Therefore, the three parts are 70,72and 74

Divide 216 into 3 parts which are in AP and the product of two smaller parts is 5040pls help me!!!

Answer»

Step-by-step explanation:

Let the THREE NUMBERS are a-d, a ,a+d
Sum of these three numbers is 216
(a-d)+a+(a+d)=216
3a =216 =72

a=72

Product of two smaller parts will be 5040

$(a - d)a = 5040$

according to formula

(72-d) 72=5040

Divide both sides by 72

(72-d)=70

72-70=d

2-d

We have a number A =72 and D=2 so,three numbers are :

a-d=72-2=70

a=72

a+d=72+2=74

Therefore, the three parts are 70,72and 74

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Divide 216 into 3 parts which are in AP and the product of two smaller parts is 5040pls help me!!!​

Product of two smaller parts will be 5040

Divide both sides by 72

We have a number A =72 and D=2 so,three numbers are :

Therefore, the three parts are 70,72and 74

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Divide 216 into 3 parts which are in AP and the product of two smaller parts is 5040pls help me!!!