Divide 207 in three parts, such that all parts are in A.P. and product

1.	Divide 207 in three parts, such that all parts are in A.P. and product of two smalleparts will be 4623.
Answer» Let the three parts of 207 in A.P be (a - d) , a , (a + d) where, a > d Now, clearly, (a + d) > a > (a - d) Now, A to Q, (a - d) + a + (a + d) = 207 => 3a = 207 => a = 69 --- (i) and, (a - d) x a = 4623 => 69 (69 - d) = 4623 => d = (4761 - 4623)/69 = 2 Hence, a = 69 and d = 2 so, (a - d) = 67, a = 69 and (a + d) = 71

Divide 207 in three parts, such that all parts are in A.P. and product of two smalleparts will be 4623.

Answer»

Let the three parts of 207 in A.P be (a - d) , a , (a + d) where, a > d

Now, clearly, (a + d) > a > (a - d)

Now, A to Q,

(a - d) + a + (a + d) = 207

=> 3a = 207

=> a = 69 --- (i) and,

(a - d) x a = 4623

=> 69 (69 - d) = 4623

=> d = (4761 - 4623)/69 = 2

Hence, a = 69 and d = 2

so, (a - d) = 67, a = 69 and (a + d) = 71