Divide 184 into two parts such that one-third of one part may exceed o

1.	Divide 184 into two parts such that one-third of one part may exceed one- seventh of the other part by 8.
Answer» Let the two parts be x and (184 – x)Then, = (1/3)x – (1/7) (184 – x) = 8 = (1/3)x – (184/7) + (x/7) = 8 Transposing – (184/7) to LHS and it becomes (184/7) = (1/3) x + (x/7) = 8 + (184/7) = [(7 + 3)/21]x = (56 +184)/7 = (10/21) x = 240/7 Multiplying both side by (21/10) = (10/21)x × (21/10) = (240/7) × (21/10) = x = (240 × 21)/ (7 × 10) = x = (24 × 3)/ (1 × 1) = x = 72

Divide 184 into two parts such that one-third of one part may exceed one- seventh of the other part by 8.

Answer»

Let the two parts be x and (184 – x)Then,

= (1/3)x – (1/7) (184 – x) = 8

= (1/3)x – (184/7) + (x/7) = 8

Transposing – (184/7) to LHS and it becomes (184/7)

= (1/3) x + (x/7) = 8 + (184/7)

= [(7 + 3)/21]x = (56 +184)/7

= (10/21) x = 240/7

Multiplying both side by (21/10)

= (10/21)x × (21/10) = (240/7) × (21/10)

= x = (240 × 21)/ (7 × 10)

= x = (24 × 3)/ (1 × 1)

= x = 72