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Divide 16 into 2 parts such that twice of the square of larger part exceeds the square of the smaller part by 164 |
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Answer» LET the no.s be X and y. larger PART be x. x+y=16 x=16/y 2x^2-y^2=164 2*(16/y)^2-y^2=164 solve it for GETTING ANSWER |
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