1.

Divide 15 into 3 parts which are in AP and the sum of their squares is 83.

Answer»

LET a-d,a,a+d are the three parts which are in Ap

→given a-d+a+a+d=15

→3a=15

→a=5

now, sum of their squares is 83

→(a-d)²+a²+(a+d)²=83

→a²+d²+a²+a²+d²=83

→3a²+2d²=83

→3(25)+2d²=83

→75+2d²=83

→2d²=8

d²=4

d=±2

then the NUMBERS will be 3,5,7

the LEAST value is 3


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