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Distance of the Point (4 ,a) from x-axis is half of its distance from y-axis then a=?A) 2B) 8C) 4D) 6 |
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Answer» Answer: please.followme Step-by-step explanation: The value of a is 2 Step-by-step explanation: We KNOW, Distance is given as : \sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2} } (x 2
−x 1
) 2 +(y 2
−y 1
) 2
Finding the distance of the point ( 4 , a ) from x-axis : The perpendicular from point ( 4 , a ) on x - axis will fall on ( 4 , 0 ) Substituting the VALUES in the distance formula , = \sqrt{(4-4)^{2}+(0-a)^{2} } (4−4) 2 +(0−a) 2
= √a² = a So, The distance of the point ( 4 , a ) from x-axis is Similarly, Finding the distance of the point ( 4 , a ) from y-axis : The perpendicular from point ( 4 , a ) on y - axis will fall on ( 0 , a ) Substituting the values in the distance formula , = \sqrt{(4-0)^{2}+(a-a)^{2} } (4−0) 2 +(a−a) 2
= √4² = 4 So, The distance of the point ( 4 , a ) from y-axis is 4 According to question, The distance of the point ( 4, a ) from x-axis is HALF the distance from y-axis, that is , a=\frac{1}{2} *4A= 2 1
∗4 a = 2 Hence, The value of a is 2 |
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