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Distance between (x,1)and (-2,3) is 2√2 then x= |
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Answer»
Distance = √( x2 -x1)²+( y2-y1)² Here points are(X, -1)and (-2,3) Distance between the points on=2√2. Here x1=x, x2=-2,y1=1,y2=3 2√2 = √(-2-x)²+ (3-1)² Squaring on both SIDES..... (2√2)²= [√(-2-x) ²+(3-1)²] ² 8 = (-2-x)² +(3-1)² 8 = [(2)²+x²-2×(2)(x) +(3)²+1²-2×(3)(1)] [SINCE (a-b) ²= a²+b²-2ab] 8 = 4+x²- 4x+9 +1-6 8 = x² -4x+8 X² -4x = 0 X(x-4) = 0 X-4 = 0/x :. X = 4 Hope it helps you...... Please MARK it as brain liest ANSWER..... Follow me....... ❤ |
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