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Distance between two image formed by upper and lower part of the point object placed at `30` cm from given lens is `(60+x)`cm, then the value of `x` is |
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Answer» Correct Answer - 6 `f/(f_(L))=(3/2-1)(1/20-1/20)` `implies f_(L)=20cm` `1/f=1/(-10)-2/20=-1/5` `1/v+1/(-30)=1/(-5)implies1/v=1/30-1/5` for lens `1/v-1/(-30)=1/20` |
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