Displacement x=t^3-12t+10.The acceleration of particle when velocity i

1.	Displacement x=t^3-12t+10.The acceleration of particle when velocity is 0
Answer» acceleration =12 m/s²Explanation: DIFFERENTIATE DISPLACEMENT x with respect to tSo dV=d(x) /dtdv=d(t³-12t+10)/dt=3t²-123t²-12=0t=2Now again on DIFFERENTIATING this EQUATION we get slope of acceleration a=dV/dta=d(3t²-12)/dt=6tSo we get a=6t. —(I) Now put the value of time as 2 in the eq(i) We get a=6×2So acceleration at velocity =6t is 12 m/s²

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Displacement x=t^3-12t+10.The acceleration of particle when velocity is 0

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