discuss the nature of a solution of quadratic equation X2 - 4x+4=0
Answer»
x2 −4x+4=0 Comparing the given equation with the quadratic equation ax2+bx+c=0 a=1,b=−4 and c=4 Discriminant, Δ=b2 −4ac=(−4)2−4×1×4=16−16=0 Since the discriminant =0 so, the roots of the given quadratic equation are real and equal.