Directions: In the following question, two statements are numbered as

1.	Directions: In the following question, two statements are numbered as I and II. On solving these statements, we get quantities A and B respectively. Solve both quantities and choose the correct option.Quantity I: When 5 is subtracted from one-third of one-fifth of a number, the result is 1/30 of the same number. Find the number.Quantity II: A bag contains an equal number of ₹ 50, ₹ 100, and ₹ 200 notes. If total amount in the bag is ₹ 10500. Find the number of notes of each kind.1.Quantity I ≤ Quantity II2.Quantity I ≥ Quantity II3.Quantity I > Quantity II4.Quantity I < Quantity II5.Quantity I = Quantity II or no relation
Answer» Correct Answer - Option 3 : Quantity I > Quantity II Quantity I: Given: [(1/3) of (1/5) of a number] – 5 = (1/30) of the same number Calculation: Let the number be x [(1/3) × (1/5) × x] – 5 = (1/30) × x ⇒ [(1/15) × x] – 5 = (1/30) × x ⇒ (x – 75)/15 = (1/30) × x ⇒ (x – 75) = (1/2) × x ⇒ 2x – 150 = x ⇒ x = 150 The number is 150. Quantity II: Given: Denomination of notes in the bag are ₹ 50, ₹ 100 and ₹ 200 Calculation: Let x be the number of notes in each bag 50x + 100x + 200x = 10500 ⇒ 350x = 10500 ⇒ x = 30 The number of notes in each bag are 30. ∴ We can deduce that Quantity I > Quantity II.

Directions: In the following question, two statements are numbered as I and II. On solving these statements, we get quantities A and B respectively. Solve both quantities and choose the correct option.Quantity I: When 5 is subtracted from one-third of one-fifth of a number, the result is 1/30 of the same number. Find the number.Quantity II: A bag contains an equal number of ₹ 50, ₹ 100, and ₹ 200 notes. If total amount in the bag is ₹ 10500. Find the number of notes of each kind.1.Quantity I ≤ Quantity II2.Quantity I ≥ Quantity II3.Quantity I > Quantity II4.Quantity I < Quantity II5.Quantity I = Quantity II or no relation

Answer» Correct Answer - Option 3 :

Quantity I > Quantity II

Quantity I:

Given:

[(1/3) of (1/5) of a number] – 5 = (1/30) of the same number

Calculation:

Let the number be x

[(1/3) × (1/5) × x] – 5 = (1/30) × x

⇒ [(1/15) × x] – 5 = (1/30) × x

⇒ (x – 75)/15 = (1/30) × x

⇒ (x – 75) = (1/2) × x

⇒ 2x – 150 = x

⇒ x = 150

The number is 150.

Quantity II:

Given:

Denomination of notes in the bag are ₹ 50, ₹ 100 and ₹ 200

Calculation:

Let x be the number of notes in each bag

50x + 100x + 200x = 10500

⇒ 350x = 10500

⇒ x = 30

The number of notes in each bag are 30.

∴ We can deduce that Quantity I > Quantity II.