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Directions: In the following question, two statements are numbered as Quantity I and Quantity II. On solving these statements, we get quantities I and II respectively. Solve both quantities and choose the correct option.In a mixture of milk and water, the quantity of water is 25% less than the quantity of milk. When 10 liters of pure milk were added then the quantity of milk becomes 60% more than the quantity of water. Quantity I: What is the quantity of water in the mixture?Quantity II: 40 litres1. Quantity 1 > Quantity 22. Quantity 1 ≥ Quantity 23. Quantity 1 < Quantity 24. Quantity 1 ≤ Quantity 25. Quantity 1 = Quantity 2 |
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Answer» Correct Answer - Option 3 : Quantity 1 < Quantity 2 Given: Q water = 25% less than Q milk Calculation: Let the quantity of milk = 100x litres ⇒ Quantity of water = (100 – 25)% of 100x ⇒ 75% of 100x = 75x litres When 10 litres of milk was added then the quantity of milk = 100x + 10 litres and the quantity of water = 75x litres According to the question, ⇒ 160% of 75x = (100x + 10) ⇒ 120x = 100x + 10 ⇒ 20x = 10 ⇒ x = 0.5 litres Quantity I: The quantity of water = 75x ⇒ 75 × 0.5 = 37.5 litres Quantity II = 40 litres ∴ Quantity I < Quantity II |
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