Dinitrogen and dihydrogen react with each other to produce ammonia acc

1.	Dinitrogen and dihydrogen react with each other to produce ammonia according to the following chemical equation:N2 (g) 3H2 (g) → 2NH3 (g)(i) Calculate the mass of ammonia produced if 2.00 x 103 g dinitrogen reacts with 1.00 x 103 g of dihydrogen.(ii) Will any of the two reactants remain unreacted?(iii) If yes, which one and what would be its mass?
Answer» N₂ (g) + 3H₂ (g) → 2NH₃ (g) 2 x 14 6 x 1 2 x 17 = 28 g = 6 g = 34 g (i) 28 g of N₂ reacts with 6 g hydrogen to form 34 g of NH₃ 2.00 x 10³ g of N₂ reacts with 1.00 x 10³ g of hydrogen to form 34/28 x 2.00 x 10³ = 2751 g of NH₃ (ii) Yes, hydrogen remains unreacted (iii) 28 g N₂ reacts with 6 g Hydrogen to form NH₃ 2 x 10³ g N₂ reacts with {6 x 2 x 10³}/{28}g Hydrogen = 428.5 g Hydrogen Hydrogen remains unreacted Mass of unreacted hydrogen = (1.00 - 0.43) x 10³ g = 2571 g

Dinitrogen and dihydrogen react with each other to produce ammonia according to the following chemical equation:N2 (g) 3H2 (g) → 2NH3 (g)(i) Calculate the mass of ammonia produced if 2.00 x 103 g dinitrogen reacts with 1.00 x 103 g of dihydrogen.(ii) Will any of the two reactants remain unreacted?(iii) If yes, which one and what would be its mass?

Answer»

N₂ (g) + 3H₂ (g) → 2NH₃ (g)

2 x 14 6 x 1 2 x 17

= 28 g = 6 g = 34 g

(i) 28 g of N₂ reacts with 6 g hydrogen to form 34 g of NH₃

2.00 x 10³ g of N₂ reacts with 1.00 x 10³ g of hydrogen to form 34/28 x 2.00 x 10³ = 2751 g of NH₃

(ii) Yes, hydrogen remains unreacted

(iii) 28 g N₂ reacts with 6 g Hydrogen to form NH₃

2 x 10³ g N₂ reacts with {6 x 2 x 10³}/{28}g Hydrogen

= 428.5 g Hydrogen

Hydrogen remains unreacted

Mass of unreacted hydrogen = (1.00 - 0.43) x 10³ g = 2571 g