Dinesh is travelling on his bike. He will reach point P at 6 p. m. if

1.	Dinesh is travelling on his bike. He will reach point P at 6 p. m. if he travels at 20 km/h. He will reach point P at 2 p. m. if he travels at 30 km/h. At what speed must he travel to reach point P at 4 p. m.?1. 32 km/h2. 24 km/h3. 21 km/h4. 28 km/h
Answer» Correct Answer - Option 2 : 24 km/h Given: Dinesh is traveling on his bike. He will reach point P at 6 p.m. if he travels at 20 km/h. He will reach point P at 2 p.m. If he travelers at a speed of 30 km/h Concept used: Distance = Time × Speed Calculation: Let, when Dinesh reach point P at 4 p.m it took time t hours. ⇒ When Dinesh reach point P at 6 p.m it took time (t + 2) hours. ⇒ When Dinesh reach point P at 2 p.m it took time (t - 2) hours. As per the question, equating the distance get, ⇒ (t - 2) × 30 = (t + 2) × 20 ⇒ 3t - 6 = 2t + 4 ⇒ t = 10 Distance = (10 - 2) × 30 = 8 × 30 = 240 km. Now, 8 × 30 = 10 × speed ⇒ speed = 240/10 ∴ speed = 24km/hr

Dinesh is travelling on his bike. He will reach point P at 6 p. m. if he travels at 20 km/h. He will reach point P at 2 p. m. if he travels at 30 km/h. At what speed must he travel to reach point P at 4 p. m.?1. 32 km/h2. 24 km/h3. 21 km/h4. 28 km/h

Answer» Correct Answer - Option 2 : 24 km/h

Given:

Dinesh is traveling on his bike. He will reach point P at 6 p.m. if he travels at 20 km/h. He will reach point P at 2 p.m. If he travelers at a speed of 30 km/h

Concept used:

Distance = Time × Speed

Calculation:

Let, when Dinesh reach point P at 4 p.m it took time t hours.

⇒ When Dinesh reach point P at 6 p.m it took time (t + 2) hours.

⇒ When Dinesh reach point P at 2 p.m it took time (t - 2) hours.

As per the question, equating the distance get,

⇒ (t - 2) × 30 = (t + 2) × 20

⇒ 3t - 6 = 2t + 4

⇒ t = 10

Distance = (10 - 2) × 30 = 8 × 30 = 240 km.

Now, 8 × 30 = 10 × speed

⇒ speed = 240/10

∴ speed = 24km/hr

Discussion

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