Saved Bookmarks
| 1. |
Dimensions of class room are 20 feet * 20 feet * 12feethelpet Find the sum of the areas of its floor and four walls |
|
Answer» Answer: 1360 FEET^2 Step-by-step explanation: AREA of base (floor) = 20 feet * 20 feet = 400 feet^2 and, Area of 4 WALLS = 4 ( 20 feet * 12 feet) = 960 feet^2 Therefore, Required sum = 400 feet^2 + 960 feet^2 = 1360 feet^2 |
|