1.

Dimensions of class room are 20 feet * 20 feet * 12feethelpet Find the sum of the areas of its floor and four walls​

Answer»

Answer:

1360 FEET^2

Step-by-step explanation:

AREA of base (floor) = 20 feet * 20 feet

= 400 feet^2

and, Area of 4 WALLS = 4 ( 20 feet * 12 feet)

= 960 feet^2

Therefore,

Required sum = 400 feet^2 + 960 feet^2

= 1360 feet^2



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