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DIMENSIONALLY ANALYZE V^{2}=U^{2}+2AS

Answer»

V= FINAL VELOCITY = [LT-¹]u= initial velocity=[LT-¹]a= ACCELERATION =[LT-²]s= distance= [L]v²=u²+ 2AS=>v²-u²=2as[LT-¹]²-[LT-¹]²=2[LT-²][L][L²T-²][L²T-²]=2[L²T-²]2[L²T-²]=2[L²T-²]2 is dimensionlesshence provedRead more on Brainly.in - brainly.in/question/1669063#readmore



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