Dimension of [mu_(0)epsi_(0)]^(-(1)/(2))....

1.	Dimension of [mu_(0)epsi_(0)]^(-(1)/(2))....
Answer» `L^((1)/(2))T^(-(1)/(2))` `L^(-1)T` `L^(1)T^(-1)` `L^(-(1)/(2))T^((1)/(2))` SOLUTION :`[mu_(0)epsi_(0)]^((-1)/(2))=(1)/(sqrt(mu_(0)epsi_(0)))=` velocity `:. [mu_(0)epsi_(0)]^(-(1)/(2))=[V]` `=M^(0)L^(1)T^(-1)` `=LT^(-1)`

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