Saved Bookmarks
| 1. |
Dimension of (1)/(2)epsi_(0)E^(2) is...... epsi_(0) permittive of vaccum E= electric field |
|
Answer» `ML^(1)T^(-2)` `:. [(1)/(2)epsi_(0)E^(2)]=(["Energy"])/(["VOLUME"])` `=(ML^(2)T^(-2))/(L^(3))` `=ML^(-1)T^(-2)` |
|