1.

Dimension of (1)/(2)epsi_(0)E^(2) is...... epsi_(0) permittive of vaccum E= electric field

Answer»

`ML^(1)T^(-2)`
`ML^(-1)T^(-2)`
`ML^(2)T^(-1)`
`MLT^(-1)`

Solution :`(1)/(2)epsi_(0)E^(2)` is equation of energy DENSITY
`:. [(1)/(2)epsi_(0)E^(2)]=(["Energy"])/(["VOLUME"])`
`=(ML^(2)T^(-2))/(L^(3))`
`=ML^(-1)T^(-2)`


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