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Differentiation wrt xy= 1/cosecx + cotx |
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Answer» dy/dx = 1/2 SEC x/2 Step-by-step explanation: Y='I/ cosecx + cot x we know COSEC x=1/sinx and cot x=cos x /sin x we get , y.= sin x/ 1+cos x y= 2sinx/2 cosx/2. / 2cos^x/2 y = tanx/2 now differentiate with respect to x dy/dx =1/2sec ^x/2 |
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