Differentiation of sin Omega t×d Omega t

1.	Differentiation of sin Omega t×d Omega t
Answer» Answer: dx / dt will GIVE us the velocity(v) of the particle in simple HARMONIC motion. THEREFORE, v = A cos(omegat + phi) d(omega*t + phi)/dt because of CHAIN RULE. Here, we've used the chain rule as well as the rule of differentiation of trig functions that is the differentiation of sin function in this case

Answer»

Answer:

dx / dt will GIVE us the velocity(v) of the particle in simple HARMONIC motion. THEREFORE, v = A cos(omega*t + phi) * d(omega*t + phi)/dt because of CHAIN RULE. Here, we've used the chain rule as well as the rule of differentiation of trig functions that is the differentiation of sin function in this case

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Differentiation of sin Omega t×d Omega t

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