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Differentiate sin x^5 |
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Answer» Grt but x pwr 5 Answer:dydx=cos(x5)⋅5x4Explanation:y=sinx5Using the\xa0chain rule:If\xa0y=y(u)\xa0and\xa0u=u(x)\xa0then,\xa0dydx=(dydu)⋅(dudx)y=sinudydx=cosuu=x5dudx=5x4Therefore,dydx=(dydu)⋅(dudx)dydx=cosu⋅5x4Substitute\xa0u\xa0back in and rearrange:dydx=cos(x5)⋅5x4 |
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