1.

Differentiate f(x)=e^(x^7-4x^3+x)​

Answer»

ANSWER:

f'(X)= e^({x^{7} -4x^{3}+x }) (x^{7} -4x^{3}+x )

Differentiating again...

f''(x)= e^{(x^{7}-4x^{3}+x) }. 7x^{2} -12x^{2} +1

HOPE U understand.....



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