1.

Differentiate: e^5ln(tan5x)answer fast if can​

Answer»

Answer:

Step-by-step explanation:

Using,

e^ln(a)=a

And,

ln(a^x)=x⋅ln(a)

we get,

e^5ln(TAN(5x))

e^ln(tan(5x))5

=tan5(5x)

from there, we can use the chain RULE

(U5)'⋅(tan(5x))'

where

(tan(5x))=sec^2(5x)⋅5

which gives,

5u4sec2(5x)⋅5

In total that becomes,

25tan^4(5x)sec^2(5x)


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