1.

Differentiate 8e^cos2x w.r.t x.(a) 16 sin⁡2x e^cos2x(b) -16 sin⁡2x e^cos2x(c) -16 sin⁡2x e^-cos⁡2x(d) 16 sin⁡2x e^-cos⁡2xI had been asked this question in an interview.The doubt is from Exponential and Logarithmic Functions in section Continuity and Differentiability of Mathematics – Class 12

Answer»

The correct option is (b) -16 sin⁡2X e^cos2x

Best explanation: Consider y=8e^cos2x

Differentiating w.r.t X by USING CHAIN rule, we get

\(\frac{dy}{dx}=\frac{d}{dx}\)(8e^cos2x)

=8e^cos2x\(\frac{d}{dx}\) (cos⁡2x)

=8e^cos2x(-sin⁡2x)\(\frac{d}{dx}\) (2x)

=8e^cos2x(-sin⁡2x)(2)

∴\(\frac{dy}{dx}\)=-16 sin⁡2x e^cos2x



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