Differenciate w.r.t to x Ans:

1.	Differenciate w.r.t to x Ans:
Answer» $\huge\bf{\red{\overbrace{\underbrace{\purple{Given:}}}}}$ ★ $y=\dfrac{2}{<klux>X</klux>}+\frac{x}{2}$ $\huge\bf{\red{\overbrace{\underbrace{\purple{To\:\:Find:}}}}}$ ★The DIFFERENTIATION of y W. R. t. x. $\huge\bf{\red {\overbrace{\underbrace{\purple{Answer:}}}}}$ We have, $y=\dfrac{2}{x}+\frac{x}{2}$ So, $\implies \dfrac{dy}{dx} =\dfrac{d[\dfrac{2}{x}+\dfrac{x}{2}]}{dx}$ $\implies \dfrac{dy}{dx}=\dfrac{d[2x^{-1}+\frac{1}{2}(x) ]}{dx}$ $\implies \dfrac{dy}{dx}=\dfrac{d[2x^{-1}]}{dx}+\dfrac{1}{2}\dfrac{d[x]}{dx}$ $\implies \dfrac{dy}{dx}=2\frac{d[x^{-1}]}{dx}+\dfrac{1}{2}\times 1$ $\large\orange{\boxed{\bf{\purple{y=a^{n}, \dfrac{dy}{dx}=na^{n-1}}}}}$ $\implies \dfrac{dy}{dx}=-2x^{-2}+\dfrac{1}{2}$ $\large\green{\boxed{\red{\sf{.\degree.\dfrac{dy}{dx}=-2x^{-2}+\dfrac{1}{2}}}}}$

Answer»

$\huge\bf{\red{\overbrace{\underbrace{\purple{Given:}}}}}$