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Diagonals of a rhombus are 20 cm and 21 cm respectively, then find the side of rhombus and its perimeter. |
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Answer» We know that in a rhombus the diagonals bisect each other at 90so let AC=20 AND BD=21 cmAD=10 AND BO=10.5 CMAB²=AD²+OB²=10²+10.5²=100+110.25=210.25So, AB = √(210.25)AB =14.5 cm is side of the rhombus Perimeter of rhombus = 4S=4(14.5)=58 cm |
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