Diagonals AC and BD of a quadrilateral ABCD intersect each other at P. Show that:ar(Δ APB) ✕ ar (Δ CPD) = ar (Δ APD) ✕ ar (Δ BPC)

Diagonals AC and BD of a quadrilateral ABCD intersect each other at P.

1.	Diagonals AC and BD of a quadrilateral ABCD intersect each other at P. Show that:ar(Δ APB) ✕ ar (Δ CPD) = ar (Δ APD) ✕ ar (Δ BPC)
Answer» Diagonals AC and BD of a quadrilateral ABCD intersect each other at P. Show that: ar(Δ APB) ✕ ar (Δ CPD) = ar (Δ APD) ✕ ar (Δ BPC)