Diagonals AC and BD of a quadrilateral ABCD intersect each other at P.

1.	Diagonals AC and BD of a quadrilateral ABCD intersect each other at P. Show that: ar (△APB)×ar(△CPD)=ar(△APD)×ar(△BPC)
Answer» Diagonals AC and BD of a quadrilateral ABCD intersect each other at P. Show that: ar $(△ A P B) \times a r (△ C P D) = a r (△ A P D) \times a r (△ B P C)$

Diagonals AC and BD of a quadrilateral ABCD intersect each other at P. Show that: ar (△APB)×ar(△CPD)=ar(△APD)×ar(△BPC)

Answer»

Diagonals AC and BD of a quadrilateral ABCD intersect each other at P. Show that:

ar $(△ A P B) \times a r (△ C P D) = a r (△ A P D) \times a r (△ B P C)$