1.

Diagonal of a square is 20 cm. Find the length and perimeter of the square.

Answer»

Diagonal of square = 20 cm.

Let side of square = x

∴ x2 + x2 = 202 ......(By Pythagoras theorem)

∴ 2x2 = 400

∴ x2 = 200

∴ x = 10 2 cm. 

Perimeter of square = 4 × 10 2 = 40 

(i) Side of square = 10 2 cm. 

(ii) Perimeter of square = 40 2 cm. 



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