1.

Diagonal of a cube is ……………… A) a√3 B) \(\frac{\sqrt3}{a}\)C) 3a D) \(\frac{a}{\sqrt3}\)

Answer»

Correct option is (A) a√3

\(\because\) Diagonal of a cuboid \(=\sqrt{l^2+b^2+h^2}\)

For a cube, l = b = h = a

\(\therefore\) Diagonal of a cube \(=\sqrt{a^2+a^2+a^2}\)

\(=\sqrt{3a^2}=\sqrt3\,a\)

Correct option is  A) a√3



Discussion

No Comment Found