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| 1. |
Determine work done by a person if he slowly lights a block of mess ‘m’ through a vertical height ‘h’ and then walks horizontally a distance ‘d’ while holding the block |
| Answer» E person lifts the block of mass m SLOWLY to a height h,force = mgdisplacement (in the direction of force) = hwork done = force × displacement = mgh When he walks horizontally a distance d while HOLDING the block,displacement = dforce = mg (PERPENDICULAR to displacement)so work done = 0So total work done = mgh + 0 = mgh | |