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Determine whether the following reaction will be spontaneous or non- spontaneous under standard conditions. `Zn_((s)) +Cu^(2+) to Zn^(2+) + Cu_((s)) " "DeltaH^(@) =- 219 kJ, DeltaS^(@) =- 21 JK^(-1)` |
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Answer» Correct Answer - The reaction is spontaneous. Given : `DeltaH^(@) =- 219 kJ` `Delta S^(@) =-21 JK^(-1) = 0.021 kJK^(-1)` `Delta G^(@)= ?` for standard conditions : Pressure = 1 atm Temperature = T = 298 K `Delta G^(@) = Delta H^(@) = T Delta S^(@)` `=- 219 - 298 xx (-0.021)` `=- 219 + 6.258` `=- 212 .742 kJ` Since `Delta G lt 0` the reaction is spontaneous. |
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