Determine weather the given quadratic equation has real roots 2x^2 +5�

1.	Determine weather the given quadratic equation has real roots 2x^2 +5√3+ 16=0
Answer» Answer: $2 {x}^{2} + 5 \sqrt{3} + 16 = 0 \\ d = {b}^{2} - 4ac \\ = 0 - 4(2)(5 \sqrt{3 } + 16) \\ = - (40 \sqrt{3 } + 128)$ since D is in negative the QE has no REAL ROOTS

Determine weather the given quadratic equation has real roots 2x^2 +5√3+ 16=0

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Answer:

$2 {x}^{2} + 5 \sqrt{3} + 16 = 0 \\ d = {b}^{2} - 4ac \\ = 0 - 4(2)(5 \sqrt{3 } + 16) \\ = - (40 \sqrt{3 } + 128)$

since D is in negative the QE has no REAL ROOTS

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Determine weather the given quadratic equation has real roots 2x^2 +5√3+ 16=0

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