1.

Determine the work done by the gas which expands from 100 mL to 250 mL. under a constant pressure fo 2 atm.

Answer»

he work DONE by a GAS which expands from volume v1 to v2 under a constant pressure p is in this case, p = 2atmv1 =100 ml= 0.1 litv2= 250ML = 0.25 lit so, the work done will be again, 1L atm = 101.33 JOULESO, work done = 101.33×0.3 = 30.399 joulesHope this HELPS....



Discussion

No Comment Found