1.

Determine the value of log 128base root 2

Answer»

Answer:

14

Step-by-step EXPLANATION:

Let log 128 to the BASE2 be x

Then,

( \sqrt{2})^{x} = 128 \\\\ (2^{\frac{1}{2}})^{x} = 128 \\\\ (2^ \frac{x}{2} ) = 2^{7} \\\\ x/2 = 7 \\\\ x = 7(2) \\\\ x = 14 \\\\ log \:128 \:\:to \:\:the \:\:base \:\: \sqrt{2} = 14



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