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Determine the specific agevity of a fluidhuiving viscosity 0.07 poise and kinematicWiscosity 0.042 stokes. |
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Answer» Specific gravityS(for\ liquids)=\dfrac{\rho_L}{\rho_{H_2O}}S(for liquids)= ρ H 2 O ρ L Density of water \rho_{H_2O}=1000kg/m^3ρ H 2 O =1000kg/m 3 Given\mu_L=0.07\text{ POISE}=7\times10^{-3}Ns/m^2,μ L =0.07 poise=7×10 −3 Ns/m 2 ,\nu_L=0.042St=4.2\times10^{-6}m^2/sν L =0.042St=4.2×10 −6 m 2 /sUse the relation\nu_L=\dfrac{\mu_L}{\rho_L}ν L = ρ L μ L ThenS=\dfrac{\rho_L}{\rho_{H_2O}}=\dfrac{\mu_L}{\nu_L\cdot\rho_{H_2O}}S= ρ H 2 O ρ L = ν L ⋅ρ H 2 O μ L S=\dfrac{7\times10^{-3}Ns/m^2}{4.2\times10^{-6}m^2/s\cdot1000kg/m^3}=\dfrac{5}{3}\approx1.667S= 4.2×10 −6 m 2 /s⋅1000kg/m 3 7×10 −3 Ns/m 2 = 35 ≈1.667 answer |
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